-16y^2+195+87=0

Solution for -16y^2+195+87=0 equation:

-16y^2+195+87=0

We add all the numbers together, and all the variables

-16y^2+282=0

a = -16; b = 0; c = +282;
Δ = b2-4ac
Δ = 02-4·(-16)·282
Δ = 18048
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{18048}=\sqrt{64*282}=\sqrt{64}*\sqrt{282}=8\sqrt{282}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{282}}{2*-16}=\frac{0-8\sqrt{282}}{-32}
=-\frac{8\sqrt{282}}{-32}
=-\frac{\sqrt{282}}{-4}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{282}}{2*-16}=\frac{0+8\sqrt{282}}{-32}
=\frac{8\sqrt{282}}{-32}
=\frac{\sqrt{282}}{-4}
$